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105344200003 = 7131711142599
BaseRepresentation
bin110001000011100000…
…0001110110101000011
3101001220121200211110011
41202013000032311003
53211221103400003
6120221111445351
710416345632350
oct1420700166503
9331817624404
10105344200003
1140749066719
12184bb686857
139c1aa73573
145154b1d627
152b184d146d
hex188700ed43

105344200003 has 8 divisors (see below), whose sum is σ = 120402617600. Its totient is φ = 90288093960.

The previous prime is 105344199977. The next prime is 105344200021. The reversal of 105344200003 is 300002443501.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 105344200003 - 29 = 105344199491 is a prime.

It is a super-2 number, since 2×1053442000032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (105344200063) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 479103 + ... + 663496.

It is an arithmetic number, because the mean of its divisors is an integer number (15050327200).

Almost surely, 2105344200003 is an apocalyptic number.

105344200003 is a deficient number, since it is larger than the sum of its proper divisors (15058417597).

105344200003 is a wasteful number, since it uses less digits than its factorization.

105344200003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1155777.

The product of its (nonzero) digits is 1440, while the sum is 22.

Adding to 105344200003 its reverse (300002443501), we get a palindrome (405346643504).

The spelling of 105344200003 in words is "one hundred five billion, three hundred forty-four million, two hundred thousand, three".

Divisors: 1 7 13171 92197 1142599 7998193 15049171429 105344200003