Search a number
-
+
1053513453131 = 2087504798013
BaseRepresentation
bin11110101010010100100…
…10111000111001001011
310201201022011102111201122
433111022102320321023
5114230043421000011
62123551041305455
7136054021412246
oct17251222707113
93651264374648
101053513453131
11376879974317
1215021763528b
1378465c053c9
1438dc163825d
151c60e7c43db
hexf54a4b8e4b

1053513453131 has 4 divisors (see below), whose sum is σ = 1054018253232. Its totient is φ = 1053008653032.

The previous prime is 1053513453121. The next prime is 1053513453173. The reversal of 1053513453131 is 1313543153501.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1053513453131 - 26 = 1053513453067 is a prime.

It is a super-3 number, since 3×10535134531313 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1053513453091 and 1053513453100.

It is not an unprimeable number, because it can be changed into a prime (1053513453121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 252396920 + ... + 252401093.

It is an arithmetic number, because the mean of its divisors is an integer number (263504563308).

Almost surely, 21053513453131 is an apocalyptic number.

1053513453131 is a deficient number, since it is larger than the sum of its proper divisors (504800101).

1053513453131 is an equidigital number, since it uses as much as digits as its factorization.

1053513453131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 504800100.

The product of its (nonzero) digits is 40500, while the sum is 35.

The spelling of 1053513453131 in words is "one trillion, fifty-three billion, five hundred thirteen million, four hundred fifty-three thousand, one hundred thirty-one".

Divisors: 1 2087 504798013 1053513453131