Base | Representation |
---|---|
bin | 11110101010010110101… |
… | …10111111000111010011 |
3 | 10201201100102000110001212 |
4 | 33111023112333013103 |
5 | 114230113003220103 |
6 | 2123552520050335 |
7 | 136054326221624 |
oct | 17251326770723 |
9 | 3651312013055 |
10 | 1053531304403 |
11 | 376888a57236 |
12 | 1502216039ab |
13 | 784698157a6 |
14 | 38dc3b63a4b |
15 | 1c61114d7d8 |
hex | f54b5bf1d3 |
1053531304403 has 2 divisors, whose sum is σ = 1053531304404. Its totient is φ = 1053531304402.
The previous prime is 1053531304379. The next prime is 1053531304487. The reversal of 1053531304403 is 3044031353501.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1053531304403 - 210 = 1053531303379 is a prime.
It is a super-2 number, since 2×10535313044032 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1053531304403.
It is not a weakly prime, because it can be changed into another prime (1053531304603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526765652201 + 526765652202.
It is an arithmetic number, because the mean of its divisors is an integer number (526765652202).
Almost surely, 21053531304403 is an apocalyptic number.
1053531304403 is a deficient number, since it is larger than the sum of its proper divisors (1).
1053531304403 is an equidigital number, since it uses as much as digits as its factorization.
1053531304403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32400, while the sum is 32.
Adding to 1053531304403 its reverse (3044031353501), we get a palindrome (4097562657904).
The spelling of 1053531304403 in words is "one trillion, fifty-three billion, five hundred thirty-one million, three hundred four thousand, four hundred three".
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