Base | Representation |
---|---|
bin | 11110101010110011100… |
… | …01111011001010001001 |
3 | 10201201222021021102001222 |
4 | 33111121301323022021 |
5 | 114231111422401423 |
6 | 2124032521451425 |
7 | 136063324545146 |
oct | 17253161731211 |
9 | 3651867242058 |
10 | 1053773247113 |
11 | 3769a2587394 |
12 | 15028a640b75 |
13 | 784a7996962 |
14 | 39007d433cd |
15 | 1c6274e03c8 |
hex | f559c7b289 |
1053773247113 has 2 divisors, whose sum is σ = 1053773247114. Its totient is φ = 1053773247112.
The previous prime is 1053773247103. The next prime is 1053773247133. The reversal of 1053773247113 is 3117423773501.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 771229970809 + 282543276304 = 878197^2 + 531548^2 .
It is a cyclic number.
It is not a de Polignac number, because 1053773247113 - 210 = 1053773246089 is a prime.
It is a super-2 number, since 2×10537732471132 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1053773247103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526886623556 + 526886623557.
It is an arithmetic number, because the mean of its divisors is an integer number (526886623557).
Almost surely, 21053773247113 is an apocalyptic number.
It is an amenable number.
1053773247113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1053773247113 is an equidigital number, since it uses as much as digits as its factorization.
1053773247113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 370440, while the sum is 44.
The spelling of 1053773247113 in words is "one trillion, fifty-three billion, seven hundred seventy-three million, two hundred forty-seven thousand, one hundred thirteen".
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