1054013001 has 4 divisors (see below), whose sum is σ = 1405350672. Its totient is φ = 702675332.

The previous prime is 1054012997. The next prime is 1054013003. The reversal of 1054013001 is 1003104501.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1054013001 - 2² = 1054012997 is a prime.

It is a super-2 number, since 2×1054013001² = 2221886812554052002, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1054013003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 175668831 + ... + 175668836.

It is an arithmetic number, because the mean of its divisors is an integer number (351337668).

Almost surely, 2^1054013001 is an apocalyptic number.

It is an amenable number.

1054013001 is a deficient number, since it is larger than the sum of its proper divisors (351337671).

1054013001 is an equidigital number, since it uses as much as digits as its factorization.

1054013001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 351337670.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 1054013001 is about 32465.5663896381. The cubic root of 1054013001 is about 1017.6895677161.

Adding to 1054013001 its reverse (1003104501), we get a palindrome (2057117502).

The spelling of 1054013001 in words is "one billion, fifty-four million, thirteen thousand, one".