Base | Representation |
---|---|
bin | 11110101011010010001… |
… | …01110010101011010011 |
3 | 10201202122011121120111112 |
4 | 33111221011302223103 |
5 | 114232123202112431 |
6 | 2124114215203535 |
7 | 136102564065545 |
oct | 17255105625323 |
9 | 3652564546445 |
10 | 1054030113491 |
11 | 37701457a953 |
12 | 1503406765ab |
13 | 78518c717b4 |
14 | 390300c9695 |
15 | 1c63ed2dc2b |
hex | f569172ad3 |
1054030113491 has 2 divisors, whose sum is σ = 1054030113492. Its totient is φ = 1054030113490.
The previous prime is 1054030113467. The next prime is 1054030113541. The reversal of 1054030113491 is 1943110304501.
It is a weak prime.
It is an emirp because it is prime and its reverse (1943110304501) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1054030113491 is a prime.
It is a super-2 number, since 2×10540301134912 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1054030113401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527015056745 + 527015056746.
It is an arithmetic number, because the mean of its divisors is an integer number (527015056746).
Almost surely, 21054030113491 is an apocalyptic number.
1054030113491 is a deficient number, since it is larger than the sum of its proper divisors (1).
1054030113491 is an equidigital number, since it uses as much as digits as its factorization.
1054030113491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 32.
Adding to 1054030113491 its reverse (1943110304501), we get a palindrome (2997140417992).
The spelling of 1054030113491 in words is "one trillion, fifty-four billion, thirty million, one hundred thirteen thousand, four hundred ninety-one".
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