1054055031313 has 4 divisors (see below), whose sum is σ = 1054082001520. Its totient is φ = 1054028061108.

The previous prime is 1054055031301. The next prime is 1054055031319. The reversal of 1054055031313 is 3131305504501.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1054055031313 - 2³⁷ = 916616077841 is a prime.

It is a super-2 number, since 2×1054055031313² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1054055031319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13426395 + ... + 13504672.

It is an arithmetic number, because the mean of its divisors is an integer number (263520500380).

Almost surely, 2^{1054055031313} is an apocalyptic number.

It is an amenable number.

1054055031313 is a deficient number, since it is larger than the sum of its proper divisors (26970207).

1054055031313 is an equidigital number, since it uses as much as digits as its factorization.

1054055031313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26970206.

The product of its (nonzero) digits is 13500, while the sum is 31.

The spelling of 1054055031313 in words is "one trillion, fifty-four billion, fifty-five million, thirty-one thousand, three hundred thirteen".