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105433129 is a prime number
BaseRepresentation
bin1100100100011…
…00100000101001
321100101120001201
412102030200221
5203442330004
614243444201
72420111134
oct622144051
9240346051
10105433129
115457251a
122b386661
1318ac6789
141000721b
1593c96a4
hex648c829

105433129 has 2 divisors, whose sum is σ = 105433130. Its totient is φ = 105433128.

The previous prime is 105433117. The next prime is 105433213. The reversal of 105433129 is 921334501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 90687529 + 14745600 = 9523^2 + 3840^2 .

It is a cyclic number.

It is not a de Polignac number, because 105433129 - 29 = 105432617 is a prime.

It is a super-2 number, since 2×1054331292 = 22232289381461282, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 105433097 and 105433106.

It is not a weakly prime, because it can be changed into another prime (105433429) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52716564 + 52716565.

It is an arithmetic number, because the mean of its divisors is an integer number (52716565).

Almost surely, 2105433129 is an apocalyptic number.

It is an amenable number.

105433129 is a deficient number, since it is larger than the sum of its proper divisors (1).

105433129 is an equidigital number, since it uses as much as digits as its factorization.

105433129 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3240, while the sum is 28.

The square root of 105433129 is about 10268.0635467453. The cubic root of 105433129 is about 472.4171970277.

The spelling of 105433129 in words is "one hundred five million, four hundred thirty-three thousand, one hundred twenty-nine".