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10544303134433 is a prime number
BaseRepresentation
bin1001100101110000100101…
…1100010101011011100001
31101100000200121121101021202
42121130021130111123201
52340224213100300213
634231552550130545
72135541442554125
oct231341134253341
941300617541252
1010544303134433
1133a58a5259102
121223681950a55
135b6428a04933
142864c0221585
15134435210b58
hex997097156e1

10544303134433 has 2 divisors, whose sum is σ = 10544303134434. Its totient is φ = 10544303134432.

The previous prime is 10544303134399. The next prime is 10544303134439. The reversal of 10544303134433 is 33443130344501.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9649863854929 + 894439279504 = 3106423^2 + 945748^2 .

It is a cyclic number.

It is not a de Polignac number, because 10544303134433 - 226 = 10544236025569 is a prime.

It is a super-2 number, since 2×105443031344332 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10544303134439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5272151567216 + 5272151567217.

It is an arithmetic number, because the mean of its divisors is an integer number (5272151567217).

Almost surely, 210544303134433 is an apocalyptic number.

It is an amenable number.

10544303134433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10544303134433 is an equidigital number, since it uses as much as digits as its factorization.

10544303134433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 311040, while the sum is 38.

Adding to 10544303134433 its reverse (33443130344501), we get a palindrome (43987433478934).

The spelling of 10544303134433 in words is "ten trillion, five hundred forty-four billion, three hundred three million, one hundred thirty-four thousand, four hundred thirty-three".