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10550113441 = 71507159063
BaseRepresentation
bin10011101001101010…
…11111010010100001
31000020020220021220021
421310311133102201
5133101312112231
64502513313441
7522304325140
oct116465372241
930206807807
1010550113441
11452429a41a
122065265881
13cc196a49a
14721241757
1541b324811
hex274d5f4a1

10550113441 has 4 divisors (see below), whose sum is σ = 12057272512. Its totient is φ = 9042954372.

The previous prime is 10550113403. The next prime is 10550113459. The reversal of 10550113441 is 14431105501.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14431105501 = 44017327853.

It is a cyclic number.

It is not a de Polignac number, because 10550113441 - 29 = 10550112929 is a prime.

It is a super-2 number, since 2×105501134412 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10550113241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 753579525 + ... + 753579538.

It is an arithmetic number, because the mean of its divisors is an integer number (3014318128).

Almost surely, 210550113441 is an apocalyptic number.

It is an amenable number.

10550113441 is a deficient number, since it is larger than the sum of its proper divisors (1507159071).

10550113441 is an equidigital number, since it uses as much as digits as its factorization.

10550113441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1507159070.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 10550113441 its reverse (14431105501), we get a palindrome (24981218942).

The spelling of 10550113441 in words is "ten billion, five hundred fifty million, one hundred thirteen thousand, four hundred forty-one".

Divisors: 1 7 1507159063 10550113441