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105550356433 = 151699008983
BaseRepresentation
bin110001001001101001…
…0101001111111010001
3101002102222121122220111
41202103102221333101
53212131342401213
6120253354241321
710424431140454
oct1422322517721
9332388548814
10105550356433
1140844474035
1218558726241
139c516a4b12
14517426549b
152b2b654a3d
hex18934a9fd1

105550356433 has 4 divisors (see below), whose sum is σ = 106249365568. Its totient is φ = 104851347300.

The previous prime is 105550356409. The next prime is 105550356451. The reversal of 105550356433 is 334653055501.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 105550356433 - 233 = 96960421841 is a prime.

It is a super-2 number, since 2×1055503564332 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (105550356733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 349504341 + ... + 349504642.

It is an arithmetic number, because the mean of its divisors is an integer number (26562341392).

Almost surely, 2105550356433 is an apocalyptic number.

It is an amenable number.

105550356433 is a deficient number, since it is larger than the sum of its proper divisors (699009135).

105550356433 is an equidigital number, since it uses as much as digits as its factorization.

105550356433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 699009134.

The product of its (nonzero) digits is 405000, while the sum is 40.

The spelling of 105550356433 in words is "one hundred five billion, five hundred fifty million, three hundred fifty-six thousand, four hundred thirty-three".

Divisors: 1 151 699008983 105550356433