1055541131 has 2 divisors, whose sum is σ = 1055541132. Its totient is φ = 1055541130.

The previous prime is 1055541121. The next prime is 1055541229. The reversal of 1055541131 is 1311455501.

It is a weak prime.

It is an emirp because it is prime and its reverse (1311455501) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1055541131 is a prime.

It is a super-2 number, since 2×1055541131² = 2228334158465518322, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1055541131.

It is not a weakly prime, because it can be changed into another prime (1055541121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527770565 + 527770566.

It is an arithmetic number, because the mean of its divisors is an integer number (527770566).

Almost surely, 2^1055541131 is an apocalyptic number.

1055541131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1055541131 is an equidigital number, since it uses as much as digits as its factorization.

1055541131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1500, while the sum is 26.

The square root of 1055541131 is about 32489.0924927121. The cubic root of 1055541131 is about 1018.1811527325.

Adding to 1055541131 its reverse (1311455501), we get a palindrome (2366996632).

The spelling of 1055541131 in words is "one billion, fifty-five million, five hundred forty-one thousand, one hundred thirty-one".