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105554335793 is a prime number
BaseRepresentation
bin110001001001110000…
…1110101100000110001
3101002110021002211120012
41202103201311200301
53212133402221133
6120254015424305
710424510023214
oct1422341654061
9332407084505
10105554335793
1140846741865
1218559b25095
139c5246917a
1451749bd77b
152b2bb8db48
hex1893875831

105554335793 has 2 divisors, whose sum is σ = 105554335794. Its totient is φ = 105554335792.

The previous prime is 105554335751. The next prime is 105554335847. The reversal of 105554335793 is 397533455501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 77413602289 + 28140733504 = 278233^2 + 167752^2 .

It is a cyclic number.

It is not a de Polignac number, because 105554335793 - 218 = 105554073649 is a prime.

It is a super-2 number, since 2×1055543357932 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (105554335723) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52777167896 + 52777167897.

It is an arithmetic number, because the mean of its divisors is an integer number (52777167897).

Almost surely, 2105554335793 is an apocalyptic number.

It is an amenable number.

105554335793 is a deficient number, since it is larger than the sum of its proper divisors (1).

105554335793 is an equidigital number, since it uses as much as digits as its factorization.

105554335793 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4252500, while the sum is 50.

The spelling of 105554335793 in words is "one hundred five billion, five hundred fifty-four million, three hundred thirty-five thousand, seven hundred ninety-three".