Base | Representation |
---|---|
bin | 110001001001111100… |
… | …1011100011000101011 |
3 | 101002110200202020122022 |
4 | 1202103321130120223 |
5 | 3212141443234311 |
6 | 120254400215055 |
7 | 10424613436463 |
oct | 1422371343053 |
9 | 332420666568 |
10 | 105560524331 |
11 | 4084a189359 |
12 | 1856000a48b |
13 | 9c53824c22 |
14 | 5175750ba3 |
15 | 2b2c4b25db |
hex | 1893e5c62b |
105560524331 has 2 divisors, whose sum is σ = 105560524332. Its totient is φ = 105560524330.
The previous prime is 105560524327. The next prime is 105560524357. The reversal of 105560524331 is 133425065501.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 105560524331 - 22 = 105560524327 is a prime.
It is a super-2 number, since 2×1055605243312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 105560524291 and 105560524300.
It is not a weakly prime, because it can be changed into another prime (105560524301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52780262165 + 52780262166.
It is an arithmetic number, because the mean of its divisors is an integer number (52780262166).
Almost surely, 2105560524331 is an apocalyptic number.
105560524331 is a deficient number, since it is larger than the sum of its proper divisors (1).
105560524331 is an equidigital number, since it uses as much as digits as its factorization.
105560524331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54000, while the sum is 35.
Adding to 105560524331 its reverse (133425065501), we get a palindrome (238985589832).
The spelling of 105560524331 in words is "one hundred five billion, five hundred sixty million, five hundred twenty-four thousand, three hundred thirty-one".
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