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105705403341211 is a prime number
BaseRepresentation
bin11000000010001101110101…
…000001000101100110011011
3111212021100010022021020010101
4120002031311001011212123
5102323334131223404321
61012452220353000231
731156651302314332
oct3002156501054633
9455240108236111
10105705403341211
11307544564a7583
12ba324b9853077
1346c9c90c4705b
141c16251354d19
15c34990623791
hex60237504599b

105705403341211 has 2 divisors, whose sum is σ = 105705403341212. Its totient is φ = 105705403341210.

The previous prime is 105705403341119. The next prime is 105705403341233. The reversal of 105705403341211 is 112143304507501.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 105705403341211 - 245 = 70521031252379 is a prime.

It is a super-3 number, since 3×1057054033412113 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (105705403041211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52852701670605 + 52852701670606.

It is an arithmetic number, because the mean of its divisors is an integer number (52852701670606).

Almost surely, 2105705403341211 is an apocalyptic number.

105705403341211 is a deficient number, since it is larger than the sum of its proper divisors (1).

105705403341211 is an equidigital number, since it uses as much as digits as its factorization.

105705403341211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 50400, while the sum is 37.

Adding to 105705403341211 its reverse (112143304507501), we get a palindrome (217848707848712).

The spelling of 105705403341211 in words is "one hundred five trillion, seven hundred five billion, four hundred three million, three hundred forty-one thousand, two hundred eleven".