Base | Representation |
---|---|
bin | 110001010100011110… |
… | …0101000000011110001 |
3 | 101010101022021102022002 |
4 | 1202220330220003301 |
5 | 3213402400230423 |
6 | 120353413423345 |
7 | 10436432266253 |
oct | 1425074500361 |
9 | 333338242262 |
10 | 105913680113 |
11 | 40a1056953a |
12 | 1863a33ab55 |
13 | 9caba44647 |
14 | 51aa5ddcd3 |
15 | 2b4d4c1228 |
hex | 18a8f280f1 |
105913680113 has 2 divisors, whose sum is σ = 105913680114. Its totient is φ = 105913680112.
The previous prime is 105913680097. The next prime is 105913680149. The reversal of 105913680113 is 311086319501.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 104137226209 + 1776453904 = 322703^2 + 42148^2 .
It is an emirp because it is prime and its reverse (311086319501) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 105913680113 - 24 = 105913680097 is a prime.
It is a super-2 number, since 2×1059136801132 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (105913680193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52956840056 + 52956840057.
It is an arithmetic number, because the mean of its divisors is an integer number (52956840057).
Almost surely, 2105913680113 is an apocalyptic number.
It is an amenable number.
105913680113 is a deficient number, since it is larger than the sum of its proper divisors (1).
105913680113 is an equidigital number, since it uses as much as digits as its factorization.
105913680113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19440, while the sum is 38.
Adding to 105913680113 its reverse (311086319501), we get a palindrome (416999999614).
The spelling of 105913680113 in words is "one hundred five billion, nine hundred thirteen million, six hundred eighty thousand, one hundred thirteen".
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