10597131355913 has 2 divisors, whose sum is σ = 10597131355914. Its totient is φ = 10597131355912.

The previous prime is 10597131355901. The next prime is 10597131355957. The reversal of 10597131355913 is 31955313179501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6342701214784 + 4254430141129 = 2518472^2 + 2062627^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10597131355913 is a prime.

It is a super-4 number, since 4×10597131355913⁴ (a number of 53 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (10597131351913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5298565677956 + 5298565677957.

It is an arithmetic number, because the mean of its divisors is an integer number (5298565677957).

Almost surely, 2^{10597131355913} is an apocalyptic number.

It is an amenable number.

10597131355913 is a deficient number, since it is larger than the sum of its proper divisors (1).

10597131355913 is an equidigital number, since it uses as much as digits as its factorization.

10597131355913 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1913625, while the sum is 53.

The spelling of 10597131355913 in words is "ten trillion, five hundred ninety-seven billion, one hundred thirty-one million, three hundred fifty-five thousand, nine hundred thirteen".