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1062247132897 is a prime number
BaseRepresentation
bin11110111010100101101…
…11001110111011100001
310202112211211101102001121
433131102313032323201
5114400440231223042
62131553430332241
7136513321436416
oct17352267167341
93675754342047
101062247132897
1137a5508a5185
12151a544ba081
137922844a762
14395ad52610d
151c9713e6367
hexf752dceee1

1062247132897 has 2 divisors, whose sum is σ = 1062247132898. Its totient is φ = 1062247132896.

The previous prime is 1062247132889. The next prime is 1062247132901. The reversal of 1062247132897 is 7982317422601.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1045678037056 + 16569095841 = 1022584^2 + 128721^2 .

It is a cyclic number.

It is not a de Polignac number, because 1062247132897 - 23 = 1062247132889 is a prime.

It is a super-2 number, since 2×10622471328972 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1062547132897) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 531123566448 + 531123566449.

It is an arithmetic number, because the mean of its divisors is an integer number (531123566449).

Almost surely, 21062247132897 is an apocalyptic number.

It is an amenable number.

1062247132897 is a deficient number, since it is larger than the sum of its proper divisors (1).

1062247132897 is an equidigital number, since it uses as much as digits as its factorization.

1062247132897 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2032128, while the sum is 52.

The spelling of 1062247132897 in words is "one trillion, sixty-two billion, two hundred forty-seven million, one hundred thirty-two thousand, eight hundred ninety-seven".