Base | Representation |
---|---|
bin | 10011110101000010… |
… | …00110101100111011 |
3 | 1000110220021000221202 |
4 | 21322201012230323 |
5 | 133300212330042 |
6 | 4520200324415 |
7 | 524542455146 |
oct | 117241065473 |
9 | 30426230852 |
10 | 10645433147 |
11 | 4573084538 |
12 | 209117370b |
13 | 100863288b |
14 | 72db7505d |
15 | 4248a2632 |
hex | 27a846b3b |
10645433147 has 2 divisors, whose sum is σ = 10645433148. Its totient is φ = 10645433146.
The previous prime is 10645433093. The next prime is 10645433153. The reversal of 10645433147 is 74133454601.
It is a strong prime.
It is an emirp because it is prime and its reverse (74133454601) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10645433147 - 222 = 10641238843 is a prime.
It is a super-2 number, since 2×106454331472 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 10645433147.
It is not a weakly prime, because it can be changed into another prime (10645433177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5322716573 + 5322716574.
It is an arithmetic number, because the mean of its divisors is an integer number (5322716574).
Almost surely, 210645433147 is an apocalyptic number.
10645433147 is a deficient number, since it is larger than the sum of its proper divisors (1).
10645433147 is an equidigital number, since it uses as much as digits as its factorization.
10645433147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120960, while the sum is 38.
Adding to 10645433147 its reverse (74133454601), we get a palindrome (84778887748).
The spelling of 10645433147 in words is "ten billion, six hundred forty-five million, four hundred thirty-three thousand, one hundred forty-seven".
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