Base | Representation |
---|---|
bin | 1001101011111010100010… |
… | …1101100111010001010011 |
3 | 1101201010122121101011002021 |
4 | 2122332220231213101103 |
5 | 2343442302420101103 |
6 | 34352322324032311 |
7 | 2146304164143145 |
oct | 232765055472123 |
9 | 41633577334067 |
10 | 10650054456403 |
11 | 343673210455a |
12 | 1240075832697 |
13 | 5c33acc1136b |
14 | 28b67303ac95 |
15 | 137074310bbd |
hex | 9afa8b67453 |
10650054456403 has 2 divisors, whose sum is σ = 10650054456404. Its totient is φ = 10650054456402.
The previous prime is 10650054456397. The next prime is 10650054456521. The reversal of 10650054456403 is 30465445005601.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10650054456403 - 221 = 10650052359251 is a prime.
It is a super-2 number, since 2×106500544564032 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 10650054456403.
It is not a weakly prime, because it can be changed into another prime (10650054456203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5325027228201 + 5325027228202.
It is an arithmetic number, because the mean of its divisors is an integer number (5325027228202).
Almost surely, 210650054456403 is an apocalyptic number.
10650054456403 is a deficient number, since it is larger than the sum of its proper divisors (1).
10650054456403 is an equidigital number, since it uses as much as digits as its factorization.
10650054456403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864000, while the sum is 43.
The spelling of 10650054456403 in words is "ten trillion, six hundred fifty billion, fifty-four million, four hundred fifty-six thousand, four hundred three".
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