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1068240649313 is a prime number
BaseRepresentation
bin11111000101110000001…
…10101011110001100001
310210010022112020120221002
433202320012223301201
5120000224101234223
62134424252241345
7140114666462255
oct17427006536141
93703275216832
101068240649313
11382046aa7832
12153047770255
1379972086386
14399bb528265
151cbc269ce28
hexf8b81abc61

1068240649313 has 2 divisors, whose sum is σ = 1068240649314. Its totient is φ = 1068240649312.

The previous prime is 1068240649279. The next prime is 1068240649321. The reversal of 1068240649313 is 3139460428601.

1068240649313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 749034859024 + 319205790289 = 865468^2 + 564983^2 .

It is a cyclic number.

It is not a de Polignac number, because 1068240649313 - 216 = 1068240583777 is a prime.

It is a super-2 number, since 2×10682406493132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1068240649613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 534120324656 + 534120324657.

It is an arithmetic number, because the mean of its divisors is an integer number (534120324657).

Almost surely, 21068240649313 is an apocalyptic number.

It is an amenable number.

1068240649313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1068240649313 is an equidigital number, since it uses as much as digits as its factorization.

1068240649313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 746496, while the sum is 47.

The spelling of 1068240649313 in words is "one trillion, sixty-eight billion, two hundred forty million, six hundred forty-nine thousand, three hundred thirteen".