Base | Representation |
---|---|
bin | 11111100001000111011… |
… | …11001100001110110001 |
3 | 10211112020100100121001111 |
4 | 33300203233030032301 |
5 | 120220320410111032 |
6 | 2145254120433321 |
7 | 141145022305063 |
oct | 17604357141661 |
9 | 3745210317044 |
10 | 1082931332017 |
11 | 3882a5561117 |
12 | 155a67618841 |
13 | 7b1737c1732 |
14 | 3a5b2631733 |
15 | 1d282262c47 |
hex | fc23bcc3b1 |
1082931332017 has 2 divisors, whose sum is σ = 1082931332018. Its totient is φ = 1082931332016.
The previous prime is 1082931332009. The next prime is 1082931332039. The reversal of 1082931332017 is 7102331392801.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 955465195441 + 127466136576 = 977479^2 + 357024^2 .
It is a cyclic number.
It is not a de Polignac number, because 1082931332017 - 23 = 1082931332009 is a prime.
It is a super-2 number, since 2×10829313320172 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1082931332047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 541465666008 + 541465666009.
It is an arithmetic number, because the mean of its divisors is an integer number (541465666009).
Almost surely, 21082931332017 is an apocalyptic number.
It is an amenable number.
1082931332017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1082931332017 is an equidigital number, since it uses as much as digits as its factorization.
1082931332017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54432, while the sum is 40.
The spelling of 1082931332017 in words is "one trillion, eighty-two billion, nine hundred thirty-one million, three hundred thirty-two thousand, seventeen".
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