Base | Representation |
---|---|
bin | 101001101001… |
… | …110011011011 |
3 | 202112202020021 |
4 | 221221303123 |
5 | 10243403011 |
6 | 1030011311 |
7 | 161545126 |
oct | 51516333 |
9 | 22482207 |
10 | 10919131 |
11 | 6188783 |
12 | 37a6b37 |
13 | 2354032 |
14 | 16433bd |
15 | e5a471 |
hex | a69cdb |
10919131 has 2 divisors, whose sum is σ = 10919132. Its totient is φ = 10919130.
The previous prime is 10919093. The next prime is 10919141. The reversal of 10919131 is 13191901.
It is a strong prime.
It is an emirp because it is prime and its reverse (13191901) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10919131 - 211 = 10917083 is a prime.
It is a super-2 number, since 2×109191312 = 238454843590322, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10919096 and 10919105.
It is not a weakly prime, because it can be changed into another prime (10919141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5459565 + 5459566.
It is an arithmetic number, because the mean of its divisors is an integer number (5459566).
Almost surely, 210919131 is an apocalyptic number.
10919131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10919131 is an equidigital number, since it uses as much as digits as its factorization.
10919131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 243, while the sum is 25.
The square root of 10919131 is about 3304.4108400742. The cubic root of 10919131 is about 221.8516648341.
The spelling of 10919131 in words is "ten million, nine hundred nineteen thousand, one hundred thirty-one".
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