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10924991249 is a prime number
BaseRepresentation
bin10100010110010111…
…00010001100010001
31001012101022001120112
422023023202030101
5134333244204444
65004024251105
7534505615304
oct121313421421
931171261515
1010924991249
1146a6966697
12214a910a95
131051524083
14758d46b3b
1543e1c469e
hex28b2e2311

10924991249 has 2 divisors, whose sum is σ = 10924991250. Its totient is φ = 10924991248.

The previous prime is 10924991243. The next prime is 10924991377. The reversal of 10924991249 is 94219942901.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7470490624 + 3454500625 = 86432^2 + 58775^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10924991249 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10924991197 and 10924991206.

It is not a weakly prime, because it can be changed into another prime (10924991243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5462495624 + 5462495625.

It is an arithmetic number, because the mean of its divisors is an integer number (5462495625).

Almost surely, 210924991249 is an apocalyptic number.

It is an amenable number.

10924991249 is a deficient number, since it is larger than the sum of its proper divisors (1).

10924991249 is an equidigital number, since it uses as much as digits as its factorization.

10924991249 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 419904, while the sum is 50.

The spelling of 10924991249 in words is "ten billion, nine hundred twenty-four million, nine hundred ninety-one thousand, two hundred forty-nine".