1092500993553 has 4 divisors (see below), whose sum is σ = 1456667991408. Its totient is φ = 728333995700.

The previous prime is 1092500993543. The next prime is 1092500993561. The reversal of 1092500993553 is 3553990052901.

1092500993553 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1092500993553 - 2¹⁸ = 1092500731409 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1092500993496 and 1092500993505.

It is not an unprimeable number, because it can be changed into a prime (1092500993503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 182083498923 + ... + 182083498928.

It is an arithmetic number, because the mean of its divisors is an integer number (364166997852).

Almost surely, 2^{1092500993553} is an apocalyptic number.

It is an amenable number.

1092500993553 is a deficient number, since it is larger than the sum of its proper divisors (364166997855).

1092500993553 is an equidigital number, since it uses as much as digits as its factorization.

1092500993553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 364166997854.

The product of its (nonzero) digits is 1640250, while the sum is 51.

The spelling of 1092500993553 in words is "one trillion, ninety-two billion, five hundred million, nine hundred ninety-three thousand, five hundred fifty-three".