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109919251817 is a prime number
BaseRepresentation
bin110011001011110110…
…0101010110101101001
3101111201110110112200122
41212113230222311221
53300103312024232
6122255103013025
710640621140004
oct1462754526551
9344643415618
10109919251817
1142686608881
121937789a175
13a49986710b
14546a5a453b
152cd4e97312
hex1997b2ad69

109919251817 has 2 divisors, whose sum is σ = 109919251818. Its totient is φ = 109919251816.

The previous prime is 109919251721. The next prime is 109919251823. The reversal of 109919251817 is 718152919901.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 65484298201 + 44434953616 = 255899^2 + 210796^2 .

It is a cyclic number.

It is not a de Polignac number, because 109919251817 - 218 = 109918989673 is a prime.

It is a super-3 number, since 3×1099192518173 (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (109919251837) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 54959625908 + 54959625909.

It is an arithmetic number, because the mean of its divisors is an integer number (54959625909).

Almost surely, 2109919251817 is an apocalyptic number.

It is an amenable number.

109919251817 is a deficient number, since it is larger than the sum of its proper divisors (1).

109919251817 is an equidigital number, since it uses as much as digits as its factorization.

109919251817 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 408240, while the sum is 53.

The spelling of 109919251817 in words is "one hundred nine billion, nine hundred nineteen million, two hundred fifty-one thousand, eight hundred seventeen".