Search a number
-
+
110000110010113 is a prime number
BaseRepresentation
bin11001000000101101100101…
…011110110111111100000001
3112102110220111210112212121201
4121000231211132313330001
5103404220211130310423
61025541204121421201
732112150161553001
oct3100554536677401
9472426453485551
10110000110010113
113205a86a449444
121040691233a801
13494bc7300b2bb
141d240687ba001
15cab54e1e32ad
hex640b657b7f01

110000110010113 has 2 divisors, whose sum is σ = 110000110010114. Its totient is φ = 110000110010112.

The previous prime is 110000110010071. The next prime is 110000110010149. The reversal of 110000110010113 is 311010011000011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 84795974991729 + 25204135018384 = 9208473^2 + 5020372^2 .

It is a cyclic number.

It is not a de Polignac number, because 110000110010113 - 217 = 110000109879041 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 110000110010113.

It is not a weakly prime, because it can be changed into another prime (110000110040113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000055005056 + 55000055005057.

It is an arithmetic number, because the mean of its divisors is an integer number (55000055005057).

Almost surely, 2110000110010113 is an apocalyptic number.

It is an amenable number.

110000110010113 is a deficient number, since it is larger than the sum of its proper divisors (1).

110000110010113 is an equidigital number, since it uses as much as digits as its factorization.

110000110010113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 10.

Adding to 110000110010113 its reverse (311010011000011), we get a palindrome (421010121010124).

The spelling of 110000110010113 in words is "one hundred ten trillion, one hundred ten million, ten thousand, one hundred thirteen".