Base | Representation |
---|---|
bin | 1010000000010010010001… |
… | …0110110111101100101001 |
3 | 1102221120222101120202212102 |
4 | 2200010210112313230221 |
5 | 2420211020413021022 |
6 | 35221201234223145 |
7 | 2213503531433525 |
oct | 240044426675451 |
9 | 42846871522772 |
10 | 11000021220137 |
11 | 35610a0232a14 |
12 | 1297a64a24ab5 |
13 | 61a3b3943951 |
14 | 2a05922dad85 |
15 | 14120849ba92 |
hex | a01245b7b29 |
11000021220137 has 2 divisors, whose sum is σ = 11000021220138. Its totient is φ = 11000021220136.
The previous prime is 11000021220091. The next prime is 11000021220161. The reversal of 11000021220137 is 73102212000011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10686694440601 + 313326779536 = 3269051^2 + 559756^2 .
It is a cyclic number.
It is not a de Polignac number, because 11000021220137 - 210 = 11000021219113 is a prime.
It is not a weakly prime, because it can be changed into another prime (11000021223137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500010610068 + 5500010610069.
It is an arithmetic number, because the mean of its divisors is an integer number (5500010610069).
Almost surely, 211000021220137 is an apocalyptic number.
It is an amenable number.
11000021220137 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000021220137 is an equidigital number, since it uses as much as digits as its factorization.
11000021220137 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 168, while the sum is 20.
Adding to 11000021220137 its reverse (73102212000011), we get a palindrome (84102233220148).
The spelling of 11000021220137 in words is "eleven trillion, twenty-one million, two hundred twenty thousand, one hundred thirty-seven".
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