Base | Representation |
---|---|
bin | 10000000000011101101… |
… | …101001000111011010011 |
3 | 10220011022120212211021012 |
4 | 100000131231020323103 |
5 | 121010310030000313 |
6 | 2201200531521135 |
7 | 142321162504211 |
oct | 20003555107323 |
9 | 3804276784235 |
10 | 1100010000083 |
11 | 394569a71225 |
12 | 1592331591ab |
13 | 7c965b99b97 |
14 | 3b35294bcb1 |
15 | 1d9317c8da8 |
hex | 1001db48ed3 |
1100010000083 has 2 divisors, whose sum is σ = 1100010000084. Its totient is φ = 1100010000082.
The previous prime is 1100010000049. The next prime is 1100010000107. The reversal of 1100010000083 is 3800000100011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1100010000083 - 210 = 1100009999059 is a prime.
It is not a weakly prime, because it can be changed into another prime (1100010200083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550005000041 + 550005000042.
It is an arithmetic number, because the mean of its divisors is an integer number (550005000042).
Almost surely, 21100010000083 is an apocalyptic number.
1100010000083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100010000083 is an equidigital number, since it uses as much as digits as its factorization.
1100010000083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 1100010000083 its reverse (3800000100011), we get a palindrome (4900010100094).
The spelling of 1100010000083 in words is "one trillion, one hundred billion, ten million, eighty-three", and thus it is an aban number.
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