Base | Representation |
---|---|
bin | 11001000000101110011010… |
… | …100100000000111011010011 |
3 | 112102110222210212020222211011 |
4 | 121000232122210000323103 |
5 | 103404224022120100344 |
6 | 1025541432333031351 |
7 | 32112211224201331 |
oct | 3100563244007323 |
9 | 472428725228734 |
10 | 110001000550099 |
11 | 320601870aa2aa |
12 | 10406b20625557 |
13 | 494c085671b39 |
14 | 1d24110b92b51 |
15 | cab5a24a1d34 |
hex | 640b9a900ed3 |
110001000550099 has 2 divisors, whose sum is σ = 110001000550100. Its totient is φ = 110001000550098.
The previous prime is 110001000550039. The next prime is 110001000550151. The reversal of 110001000550099 is 990055000100011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110001000550099 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 110001000550099.
It is not a weakly prime, because it can be changed into another prime (110001000550039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000500275049 + 55000500275050.
It is an arithmetic number, because the mean of its divisors is an integer number (55000500275050).
Almost surely, 2110001000550099 is an apocalyptic number.
110001000550099 is a deficient number, since it is larger than the sum of its proper divisors (1).
110001000550099 is an equidigital number, since it uses as much as digits as its factorization.
110001000550099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2025, while the sum is 31.
The spelling of 110001000550099 in words is "one hundred ten trillion, one billion, five hundred fifty thousand, ninety-nine".
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