11000100119923 has 2 divisors, whose sum is σ = 11000100119924. Its totient is φ = 11000100119922.

The previous prime is 11000100119893. The next prime is 11000100120059. The reversal of 11000100119923 is 32991100100011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11000100119923 - 2¹³ = 11000100111731 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11000100119891 and 11000100119900.

It is not a weakly prime, because it can be changed into another prime (11000100119123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500050059961 + 5500050059962.

It is an arithmetic number, because the mean of its divisors is an integer number (5500050059962).

Almost surely, 2^{11000100119923} is an apocalyptic number.

11000100119923 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000100119923 is an equidigital number, since it uses as much as digits as its factorization.

11000100119923 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486, while the sum is 28.

Adding to 11000100119923 its reverse (32991100100011), we get a palindrome (43991200219934).

The spelling of 11000100119923 in words is "eleven trillion, one hundred million, one hundred nineteen thousand, nine hundred twenty-three".