Base | Representation |
---|---|
bin | 11001000000101110011010… |
… | …111011111000011010110011 |
3 | 112102110222211022000212021101 |
4 | 121000232122323320122303 |
5 | 103404224030220303312 |
6 | 1025541433115105231 |
7 | 32112211331320222 |
oct | 3100563273703263 |
9 | 472428738025241 |
10 | 110001006806707 |
11 | 3206018a692a55 |
12 | 10406b22742217 |
13 | 494c086a52883 |
14 | 1d24111940cb9 |
15 | cab5a2cdaa57 |
hex | 640b9aef86b3 |
110001006806707 has 2 divisors, whose sum is σ = 110001006806708. Its totient is φ = 110001006806706.
The previous prime is 110001006806681. The next prime is 110001006806759. The reversal of 110001006806707 is 707608600100011.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110001006806707 is a prime.
It is not a weakly prime, because it can be changed into another prime (110001006806107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000503403353 + 55000503403354.
It is an arithmetic number, because the mean of its divisors is an integer number (55000503403354).
Almost surely, 2110001006806707 is an apocalyptic number.
110001006806707 is a deficient number, since it is larger than the sum of its proper divisors (1).
110001006806707 is an equidigital number, since it uses as much as digits as its factorization.
110001006806707 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14112, while the sum is 37.
Adding to 110001006806707 its reverse (707608600100011), we get a palindrome (817609606906718).
The spelling of 110001006806707 in words is "one hundred ten trillion, one billion, six million, eight hundred six thousand, seven hundred seven".
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