11000101122019 has 2 divisors, whose sum is σ = 11000101122020. Its totient is φ = 11000101122018.

The previous prime is 11000101122013. The next prime is 11000101122133. The reversal of 11000101122019 is 91022110100011.

It is a weak prime.

It is an emirp because it is prime and its reverse (91022110100011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11000101122019 - 2³⁹ = 10450345308131 is a prime.

It is a super-2 number, since 2×11000101122019² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11000101121987 and 11000101122005.

It is not a weakly prime, because it can be changed into another prime (11000101122013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500050561009 + 5500050561010.

It is an arithmetic number, because the mean of its divisors is an integer number (5500050561010).

Almost surely, 2^{11000101122019} is an apocalyptic number.

11000101122019 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000101122019 is an equidigital number, since it uses as much as digits as its factorization.

11000101122019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 19.

The spelling of 11000101122019 in words is "eleven trillion, one hundred one million, one hundred twenty-two thousand, nineteen".