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1100010123193 is a prime number
BaseRepresentation
bin10000000000011101101…
…101100110111110111001
310220011022121010002010211
4100000131231212332321
5121010310042420233
62201200534311121
7142321163526142
oct20003555467671
93804277102124
101100010123193
1139456a045773
121592331b84a1
137c965c10c27
143b352980ac9
151d9318005cd
hex1001db66fb9

1100010123193 has 2 divisors, whose sum is σ = 1100010123194. Its totient is φ = 1100010123192.

The previous prime is 1100010123167. The next prime is 1100010123283. The reversal of 1100010123193 is 3913210100011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1086956375184 + 13053748009 = 1042572^2 + 114253^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100010123193 - 217 = 1100009992121 is a prime.

It is a super-2 number, since 2×11000101231932 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1100010123133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550005061596 + 550005061597.

It is an arithmetic number, because the mean of its divisors is an integer number (550005061597).

Almost surely, 21100010123193 is an apocalyptic number.

It is an amenable number.

1100010123193 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100010123193 is an equidigital number, since it uses as much as digits as its factorization.

1100010123193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 22.

The spelling of 1100010123193 in words is "one trillion, one hundred billion, ten million, one hundred twenty-three thousand, one hundred ninety-three".