110001019993 has 2 divisors, whose sum is σ = 110001019994. Its totient is φ = 110001019992.

The previous prime is 110001019939. The next prime is 110001020039. The reversal of 110001019993 is 399910100011.

Together with previous prime (110001019939) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105942438144 + 4058581849 = 325488^2 + 63707^2 .

It is an emirp because it is prime and its reverse (399910100011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110001019993 is a prime.

It is not a weakly prime, because it can be changed into another prime (110001019913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000509996 + 55000509997.

It is an arithmetic number, because the mean of its divisors is an integer number (55000509997).

Almost surely, 2^110001019993 is an apocalyptic number.

It is an amenable number.

110001019993 is a deficient number, since it is larger than the sum of its proper divisors (1).

110001019993 is an equidigital number, since it uses as much as digits as its factorization.

110001019993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2187, while the sum is 34.

The spelling of 110001019993 in words is "one hundred ten billion, one million, nineteen thousand, nine hundred ninety-three".