Base | Representation |
---|---|
bin | 10000000000011101101… |
… | …111001111001011011111 |
3 | 10220011022121220202120212 |
4 | 100000131233033023133 |
5 | 121010310200044413 |
6 | 2201200551403035 |
7 | 142321200254342 |
oct | 20003557171337 |
9 | 3804277822525 |
10 | 1100010549983 |
11 | 39456a307394 |
12 | 15923338347b |
13 | 7c966030277 |
14 | 3b352a52459 |
15 | 1d931886ca8 |
hex | 1001dbcf2df |
1100010549983 has 16 divisors (see below), whose sum is σ = 1129790323200. Its totient is φ = 1070642888640.
The previous prime is 1100010549943. The next prime is 1100010549991. The reversal of 1100010549983 is 3899450100011.
It is a cyclic number.
It is not a de Polignac number, because 1100010549983 - 214 = 1100010533599 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1100010549983.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1100010549943) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11086688 + ... + 11185466.
It is an arithmetic number, because the mean of its divisors is an integer number (70611895200).
Almost surely, 21100010549983 is an apocalyptic number.
1100010549983 is a deficient number, since it is larger than the sum of its proper divisors (29779773217).
1100010549983 is an equidigital number, since it uses as much as digits as its factorization.
1100010549983 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 100862.
The product of its (nonzero) digits is 38880, while the sum is 41.
Adding to 1100010549983 its reverse (3899450100011), we get a palindrome (4999460649994).
The spelling of 1100010549983 in words is "one trillion, one hundred billion, ten million, five hundred forty-nine thousand, nine hundred eighty-three".
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