110001110999953 has 2 divisors, whose sum is σ = 110001110999954. Its totient is φ = 110001110999952.

The previous prime is 110001110999939. The next prime is 110001111000091. The reversal of 110001110999953 is 359999011100011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 71373046338049 + 38628064661904 = 8448257^2 + 6215148^2 .

It is a cyclic number.

It is not a de Polignac number, because 110001110999953 - 2⁵ = 110001110999921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110001110999897 and 110001110999906.

It is not a weakly prime, because it can be changed into another prime (110001110999753) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000555499976 + 55000555499977.

It is an arithmetic number, because the mean of its divisors is an integer number (55000555499977).

Almost surely, 2^{110001110999953} is an apocalyptic number.

It is an amenable number.

110001110999953 is a deficient number, since it is larger than the sum of its proper divisors (1).

110001110999953 is an equidigital number, since it uses as much as digits as its factorization.

110001110999953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 98415, while the sum is 49.

The spelling of 110001110999953 in words is "one hundred ten trillion, one billion, one hundred ten million, nine hundred ninety-nine thousand, nine hundred fifty-three".