11000113100323 has 4 divisors (see below), whose sum is σ = 11001294520128. Its totient is φ = 10998931680520.

The previous prime is 11000113100299. The next prime is 11000113100357. The reversal of 11000113100323 is 32300131100011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11000113100323 - 2³⁷ = 10862674146851 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11000113100297 and 11000113100306.

It is not an unprimeable number, because it can be changed into a prime (11000113100423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 590695936 + ... + 590714557.

It is an arithmetic number, because the mean of its divisors is an integer number (2750323630032).

Almost surely, 2^{11000113100323} is an apocalyptic number.

11000113100323 is a deficient number, since it is larger than the sum of its proper divisors (1181419805).

11000113100323 is an equidigital number, since it uses as much as digits as its factorization.

11000113100323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1181419804.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 11000113100323 its reverse (32300131100011), we get a palindrome (43300244200334).

The spelling of 11000113100323 in words is "eleven trillion, one hundred thirteen million, one hundred thousand, three hundred twenty-three".