Base | Representation |
---|---|
bin | 100000110010000… |
… | …1101101001010001 |
3 | 2211122212101221101 |
4 | 1001210031221101 |
5 | 4223100341423 |
6 | 301053024401 |
7 | 36154643254 |
oct | 10144155121 |
9 | 2748771841 |
10 | 1100012113 |
11 | 514a23422 |
12 | 268485101 |
13 | 146b86355 |
14 | a614309b |
15 | 668897ad |
hex | 4190da51 |
1100012113 has 2 divisors, whose sum is σ = 1100012114. Its totient is φ = 1100012112.
The previous prime is 1100012093. The next prime is 1100012117. The reversal of 1100012113 is 3112100011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1092765249 + 7246864 = 33057^2 + 2692^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1100012113 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1100012113.
It is not a weakly prime, because it can be changed into another prime (1100012117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550006056 + 550006057.
It is an arithmetic number, because the mean of its divisors is an integer number (550006057).
Almost surely, 21100012113 is an apocalyptic number.
It is an amenable number.
1100012113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100012113 is an equidigital number, since it uses as much as digits as its factorization.
1100012113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 10.
The square root of 1100012113 is about 33166.4305133971. The cubic root of 1100012113 is about 1032.2839045361.
Adding to 1100012113 its reverse (3112100011), we get a palindrome (4212112124).
The spelling of 1100012113 in words is "one billion, one hundred million, twelve thousand, one hundred thirteen".
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