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110001212211043 is a prime number
BaseRepresentation
bin11001000000101110100111…
…001011011011111101100011
3112102111000100121112111001101
4121000232213023123331203
5103404224440311223133
61025541505333415231
732112216404243536
oct3100564713337543
9472430317474041
10110001212211043
11320602856272aa
1210406b7b49a517
13494c0ba47c9ba
141d24130d2ca1d
15cab5b5d6137d
hex640ba72dbf63

110001212211043 has 2 divisors, whose sum is σ = 110001212211044. Its totient is φ = 110001212211042.

The previous prime is 110001212211019. The next prime is 110001212211083. The reversal of 110001212211043 is 340112212100011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 110001212211043 - 229 = 110000675340131 is a prime.

It is a super-2 number, since 2×1100012122110432 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 110001212211043.

It is not a weakly prime, because it can be changed into another prime (110001212211083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000606105521 + 55000606105522.

It is an arithmetic number, because the mean of its divisors is an integer number (55000606105522).

Almost surely, 2110001212211043 is an apocalyptic number.

110001212211043 is a deficient number, since it is larger than the sum of its proper divisors (1).

110001212211043 is an equidigital number, since it uses as much as digits as its factorization.

110001212211043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 110001212211043 its reverse (340112212100011), we get a palindrome (450113424311054).

The spelling of 110001212211043 in words is "one hundred ten trillion, one billion, two hundred twelve million, two hundred eleven thousand, forty-three".