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1100012210137 is a prime number
BaseRepresentation
bin10000000000011101110…
…101100100011111011001
310220011022202001002220001
4100000131311210133121
5121010311111211022
62201201051133001
7142321220340421
oct20003565443731
93804282032801
101100012210137
11394570240715
12159233a44161
137c966491ac9
143b352d65481
151d931ab3b27
hex1001dd647d9

1100012210137 has 2 divisors, whose sum is σ = 1100012210138. Its totient is φ = 1100012210136.

The previous prime is 1100012210119. The next prime is 1100012210147. The reversal of 1100012210137 is 7310122100011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1017296149321 + 82716060816 = 1008611^2 + 287604^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1100012210137 is a prime.

It is not a weakly prime, because it can be changed into another prime (1100012210147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550006105068 + 550006105069.

It is an arithmetic number, because the mean of its divisors is an integer number (550006105069).

Almost surely, 21100012210137 is an apocalyptic number.

It is an amenable number.

1100012210137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100012210137 is an equidigital number, since it uses as much as digits as its factorization.

1100012210137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 84, while the sum is 19.

Adding to 1100012210137 its reverse (7310122100011), we get a palindrome (8410134310148).

The spelling of 1100012210137 in words is "one trillion, one hundred billion, twelve million, two hundred ten thousand, one hundred thirty-seven".