1100013230003 has 2 divisors, whose sum is σ = 1100013230004. Its totient is φ = 1100013230002.

The previous prime is 1100013229951. The next prime is 1100013230051. The reversal of 1100013230003 is 3000323100011.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1100013230003 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1100013230003.

It is not a weakly prime, because it can be changed into another prime (1100013230093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550006615001 + 550006615002.

It is an arithmetic number, because the mean of its divisors is an integer number (550006615002).

Almost surely, 2^{1100013230003} is an apocalyptic number.

1100013230003 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100013230003 is an equidigital number, since it uses as much as digits as its factorization.

1100013230003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 1100013230003 its reverse (3000323100011), we get a palindrome (4100336330014).

The spelling of 1100013230003 in words is "one trillion, one hundred billion, thirteen million, two hundred thirty thousand, three".