1100013320203 has 32 divisors (see below), whose sum is σ = 1308643015680. Its totient is φ = 905137390080.

The previous prime is 1100013320191. The next prime is 1100013320209. The reversal of 1100013320203 is 3020233100011.

It is a de Polignac number, because none of the positive numbers 2^k-1100013320203 is a prime.

It is a super-2 number, since 2×1100013320203² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1100013320209) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4350823 + ... + 4596703.

It is an arithmetic number, because the mean of its divisors is an integer number (40895094240).

Almost surely, 2^{1100013320203} is an apocalyptic number.

1100013320203 is a deficient number, since it is larger than the sum of its proper divisors (208629695477).

1100013320203 is a wasteful number, since it uses less digits than its factorization.

1100013320203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 246187.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 1100013320203 its reverse (3020233100011), we get a palindrome (4120246420214).

The spelling of 1100013320203 in words is "one trillion, one hundred billion, thirteen million, three hundred twenty thousand, two hundred three".