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1100021001217 is a prime number
BaseRepresentation
bin10000000000011110010…
…111000110110000000001
310220011100100120201222121
4100000132113012300001
5121010320334014332
62201202003404241
7142321355143405
oct20003627066001
93804310521877
101100021001217
113945751a5576
12159236983681
137c96824c328
143b3541b3105
151d93274d797
hex1001e5c6c01

1100021001217 has 2 divisors, whose sum is σ = 1100021001218. Its totient is φ = 1100021001216.

The previous prime is 1100021001199. The next prime is 1100021001229. The reversal of 1100021001217 is 7121001200011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 838691471601 + 261329529616 = 915801^2 + 511204^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100021001217 - 211 = 1100020999169 is a prime.

It is a super-3 number, since 3×11000210012173 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 1100021001217.

It is not a weakly prime, because it can be changed into another prime (1100021001917) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550010500608 + 550010500609.

It is an arithmetic number, because the mean of its divisors is an integer number (550010500609).

Almost surely, 21100021001217 is an apocalyptic number.

It is an amenable number.

1100021001217 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100021001217 is an equidigital number, since it uses as much as digits as its factorization.

1100021001217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28, while the sum is 16.

Adding to 1100021001217 its reverse (7121001200011), we get a palindrome (8221022201228).

The spelling of 1100021001217 in words is "one trillion, one hundred billion, twenty-one million, one thousand, two hundred seventeen".