Base | Representation |
---|---|
bin | 1010000000010010111110… |
… | …1010111010000001010011 |
3 | 1102221121110121201200221121 |
4 | 2200010233222322001103 |
5 | 2420211413010200112 |
6 | 35221232134303111 |
7 | 2213511324634462 |
oct | 240045752720123 |
9 | 42847417650847 |
10 | 11000211021907 |
11 | 356118838a888 |
12 | 1297ab84b7a97 |
13 | 61a41406a0a3 |
14 | 2a05ad5c69d9 |
15 | 141219e8e407 |
hex | a012faba053 |
11000211021907 has 2 divisors, whose sum is σ = 11000211021908. Its totient is φ = 11000211021906.
The previous prime is 11000211021881. The next prime is 11000211022033. The reversal of 11000211021907 is 70912011200011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11000211021907 - 211 = 11000211019859 is a prime.
It is not a weakly prime, because it can be changed into another prime (11000211021607) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500105510953 + 5500105510954.
It is an arithmetic number, because the mean of its divisors is an integer number (5500105510954).
Almost surely, 211000211021907 is an apocalyptic number.
11000211021907 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000211021907 is an equidigital number, since it uses as much as digits as its factorization.
11000211021907 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252, while the sum is 25.
Adding to 11000211021907 its reverse (70912011200011), we get a palindrome (81912222221918).
The spelling of 11000211021907 in words is "eleven trillion, two hundred eleven million, twenty-one thousand, nine hundred seven".
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