1100021130001 has 4 divisors (see below), whose sum is σ = 1100607184692. Its totient is φ = 1099435075312.

The previous prime is 1100021129969. The next prime is 1100021130071. The reversal of 1100021130001 is 1000311200011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 951795360000 + 148225770001 = 975600^2 + 385001^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100021130001 - 2⁵ = 1100021129969 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1100021130001.

It is not an unprimeable number, because it can be changed into a prime (1100021130071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 293024530 + ... + 293028283.

It is an arithmetic number, because the mean of its divisors is an integer number (275151796173).

Almost surely, 2^{1100021130001} is an apocalyptic number.

It is an amenable number.

1100021130001 is a deficient number, since it is larger than the sum of its proper divisors (586054691).

1100021130001 is an equidigital number, since it uses as much as digits as its factorization.

1100021130001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 586054690.

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 1100021130001 its reverse (1000311200011), we get a palindrome (2100332330012).

The spelling of 1100021130001 in words is "one trillion, one hundred billion, twenty-one million, one hundred thirty thousand, one".