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110002132332012 = 22316673549801737
BaseRepresentation
bin11001000000101111011110…
…000001011010110111101100
3112102111002201201220110201210
4121000233132001122313230
5103404233331334111022
61025542140523034420
732112251246164134
oct3100573601326754
9472432651813653
10110002132332012
1132060707a51858
121040719766ba10
13494c205c9c88b
141d241bb205ac4
15cab61ba14a0c
hex640bde05adec

110002132332012 has 24 divisors (see below), whose sum is σ = 256687037023536. Its totient is φ = 36665178170368.

The previous prime is 110002132331983. The next prime is 110002132332041. The reversal of 110002132332012 is 210233231200011.

110002132332012 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (110002132331983) and next prime (110002132332041).

It is a self number, because there is not a number n which added to its sum of digits gives 110002132332012.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 274700793 + ... + 275100944.

It is an arithmetic number, because the mean of its divisors is an integer number (10695293209314).

Almost surely, 2110002132332012 is an apocalyptic number.

110002132332012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

110002132332012 is an abundant number, since it is smaller than the sum of its proper divisors (146684904691524).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

110002132332012 is a wasteful number, since it uses less digits than its factorization.

110002132332012 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 549818417 (or 549818415 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 110002132332012 its reverse (210233231200011), we get a palindrome (320235363532023).

The spelling of 110002132332012 in words is "one hundred ten trillion, two billion, one hundred thirty-two million, three hundred thirty-two thousand, twelve".

Divisors: 1 2 3 4 6 12 16673 33346 50019 66692 100038 200076 549801737 1099603474 1649405211 2199206948 3298810422 6597620844 9166844361001 18333688722002 27500533083003 36667377444004 55001066166006 110002132332012