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1100021985 = 3358148311
BaseRepresentation
bin100000110010001…
…0000000011100001
32211122212220111000
41001210100003201
54223101200420
6301053142213
736155014116
oct10144200341
92748786430
101100021985
11514a2a887
1226848a969
13146b8a9aa
14a614690d
156688c690
hex419100e1

1100021985 has 16 divisors (see below), whose sum is σ = 1955594880. Its totient is φ = 586678320.

The previous prime is 1100021983. The next prime is 1100021999. The reversal of 1100021985 is 5891200011.

It is not a de Polignac number, because 1100021985 - 21 = 1100021983 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1100021983) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4074021 + ... + 4074290.

It is an arithmetic number, because the mean of its divisors is an integer number (122224680).

Almost surely, 21100021985 is an apocalyptic number.

1100021985 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

1100021985 is a deficient number, since it is larger than the sum of its proper divisors (855572895).

1100021985 is an equidigital number, since it uses as much as digits as its factorization.

1100021985 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8148325 (or 8148319 counting only the distinct ones).

The product of its (nonzero) digits is 720, while the sum is 27.

The square root of 1100021985 is about 33166.5793382435. The cubic root of 1100021985 is about 1032.2869925858.

Adding to 1100021985 its reverse (5891200011), we get a palindrome (6991221996).

The spelling of 1100021985 in words is "one billion, one hundred million, twenty-one thousand, nine hundred eighty-five".

Divisors: 1 3 5 9 15 27 45 135 8148311 24444933 40741555 73334799 122224665 220004397 366673995 1100021985