Base | Representation |
---|---|
bin | 10000000000011110011… |
… | …011010111111101011011 |
3 | 10220011100102200121001111 |
4 | 100000132123113331123 |
5 | 121010321130322113 |
6 | 2201202043401151 |
7 | 142321400514112 |
oct | 20003633277533 |
9 | 3804312617044 |
10 | 1100022120283 |
11 | 39457589a319 |
12 | 1592372231b7 |
13 | 7c9685517b8 |
14 | 3b3543c4c79 |
15 | 1d9328c013d |
hex | 1001e6d7f5b |
1100022120283 has 2 divisors, whose sum is σ = 1100022120284. Its totient is φ = 1100022120282.
The previous prime is 1100022120257. The next prime is 1100022120313. The reversal of 1100022120283 is 3820212200011.
It is a weak prime.
It is an emirp because it is prime and its reverse (3820212200011) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1100022120283 is a prime.
It is a super-2 number, since 2×11000221202832 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1100022120383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550011060141 + 550011060142.
It is an arithmetic number, because the mean of its divisors is an integer number (550011060142).
Almost surely, 21100022120283 is an apocalyptic number.
1100022120283 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100022120283 is an equidigital number, since it uses as much as digits as its factorization.
1100022120283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 1100022120283 its reverse (3820212200011), we get a palindrome (4920234320294).
The spelling of 1100022120283 in words is "one trillion, one hundred billion, twenty-two million, one hundred twenty thousand, two hundred eighty-three".
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