Base | Representation |
---|---|
bin | 10000000000011110011… |
… | …011011000001010011001 |
3 | 10220011100102200122012020 |
4 | 100000132123120022121 |
5 | 121010321130333423 |
6 | 2201202043405053 |
7 | 142321400516406 |
oct | 20003633301231 |
9 | 3804312618166 |
10 | 1100022121113 |
11 | 39457589aa03 |
12 | 159237223789 |
13 | 7c968551ca6 |
14 | 3b3543c52ad |
15 | 1d9328c04e3 |
hex | 1001e6d8299 |
1100022121113 has 8 divisors (see below), whose sum is σ = 1485261936000. Its totient is φ = 724065193488.
The previous prime is 1100022121007. The next prime is 1100022121117. The reversal of 1100022121113 is 3111212200011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1100022121113 - 232 = 1095727153817 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1100022121092 and 1100022121101.
It is not an unprimeable number, because it can be changed into a prime (1100022121117) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2320721538 + ... + 2320722011.
It is an arithmetic number, because the mean of its divisors is an integer number (185657742000).
Almost surely, 21100022121113 is an apocalyptic number.
It is an amenable number.
1100022121113 is a deficient number, since it is larger than the sum of its proper divisors (385239814887).
1100022121113 is an equidigital number, since it uses as much as digits as its factorization.
1100022121113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4641443631.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 1100022121113 its reverse (3111212200011), we get a palindrome (4211234321124).
The spelling of 1100022121113 in words is "one trillion, one hundred billion, twenty-two million, one hundred twenty-one thousand, one hundred thirteen".
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